Any hints and suggestions would be greatly appreciated. One starts MinimServer which then puts up a file location dialog requesting the contentDir - as if its a new installation. I've tried several other Java service wrappers with similar results. With your knowledge of Java can you please explain why its necessary to start MinimServer from the lib directory containing the mserver.jar file? And is there some way around this by passing an argument on the javaw command line with the correct startup directory and/or MinimServer configuration parameters? I have the AppDirectory path defined in the service parameters key in the registry for this service. If I don't change into the lib dir first MinimServer starts in the same manner as the automated service - without its configuration. I first have to change directory to C:\Program Files\MinimServer\lib first and then runĬ:\Program Files\Java\jre1.8.0_31\bin\javaw.exe -jar "C:\Program Files\MinimServer\lib\mserver.jar". Minim server starts normally with the correct displayName and contentDir if I run it manualy from the command line. it doesn't know the contentDir nor its correct displayName. ![]() ![]() However the MinimServer starts without its configuration i.e. Hi Simon - Using the above I've managed to get MinimServer to start as a service on Windows Server 2012 and connect to it remotely from another system running MinimWatch. They will be very helpful for other users.
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